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4(4x+5)=19x+19-3x=1
We move all terms to the left:
4(4x+5)-(19x+19-3x)=0
We add all the numbers together, and all the variables
4(4x+5)-(16x+19)=0
We multiply parentheses
16x-(16x+19)+20=0
We get rid of parentheses
16x-16x-19+20=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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