4(4x-1)=(5x+1+3x+2)

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Solution for 4(4x-1)=(5x+1+3x+2) equation: 



4(4x-1)=(5x+1+3x+2)

We move all terms to the left:

4(4x-1)-((5x+1+3x+2))=0

We add all the numbers together, and all the variables

4(4x-1)-((8x+3))=0

We multiply parentheses

16x-((8x+3))-4=0



We calculate terms in parentheses: -((8x+3)), so:

(8x+3)

We get rid of parentheses

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

16x-8x-3-4=0

We add all the numbers together, and all the variables

8x-7=0

We move all terms containing x to the left, all other terms to the right

8x=7

x=7/8

x=7/8

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