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4(4x-1)=2(2x+1)+2(2x+2)
We move all terms to the left:
4(4x-1)-(2(2x+1)+2(2x+2))=0
We multiply parentheses
16x-(2(2x+1)+2(2x+2))-4=0
We calculate terms in parentheses: -(2(2x+1)+2(2x+2)), so:We get rid of parentheses
2(2x+1)+2(2x+2)
We multiply parentheses
4x+4x+2+4
We add all the numbers together, and all the variables
8x+6
Back to the equation:
-(8x+6)
16x-8x-6-4=0
We add all the numbers together, and all the variables
8x-10=0
We move all terms containing x to the left, all other terms to the right
8x=10
x=10/8
x=1+1/4
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