4(4x-12)=16(x-3)

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Solution for 4(4x-12)=16(x-3) equation:


Simplifying
4(4x + -12) = 16(x + -3)

Reorder the terms:
4(-12 + 4x) = 16(x + -3)
(-12 * 4 + 4x * 4) = 16(x + -3)
(-48 + 16x) = 16(x + -3)

Reorder the terms:
-48 + 16x = 16(-3 + x)
-48 + 16x = (-3 * 16 + x * 16)
-48 + 16x = (-48 + 16x)

Add '48' to each side of the equation.
-48 + 48 + 16x = -48 + 48 + 16x

Combine like terms: -48 + 48 = 0
0 + 16x = -48 + 48 + 16x
16x = -48 + 48 + 16x

Combine like terms: -48 + 48 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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