4(4x-2)=6(3x-2)

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Solution for 4(4x-2)=6(3x-2) equation: 



4(4x-2)=6(3x-2)

We move all terms to the left:

4(4x-2)-(6(3x-2))=0

We multiply parentheses

16x-(6(3x-2))-8=0



We calculate terms in parentheses: -(6(3x-2)), so:

6(3x-2)

We multiply parentheses

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

16x-18x+12-8=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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