4(4x-20)=6(3x-1)

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Solution for 4(4x-20)=6(3x-1) equation: 



4(4x-20)=6(3x-1)

We move all terms to the left:

4(4x-20)-(6(3x-1))=0

We multiply parentheses

16x-(6(3x-1))-80=0



We calculate terms in parentheses: -(6(3x-1)), so:

6(3x-1)

We multiply parentheses

18x-6

Back to the equation:

-(18x-6)



We get rid of parentheses

16x-18x+6-80=0

We add all the numbers together, and all the variables

-2x-74=0

We move all terms containing x to the left, all other terms to the right

-2x=74

x=74/-2

x=-37

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