4(4x-28)=2(x+42)

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Solution for 4(4x-28)=2(x+42) equation: 



4(4x-28)=2(x+42)

We move all terms to the left:

4(4x-28)-(2(x+42))=0

We multiply parentheses

16x-(2(x+42))-112=0



We calculate terms in parentheses: -(2(x+42)), so:

2(x+42)

We multiply parentheses

2x+84

Back to the equation:

-(2x+84)



We get rid of parentheses

16x-2x-84-112=0

We add all the numbers together, and all the variables

14x-196=0

We move all terms containing x to the left, all other terms to the right

14x=196

x=196/14

x=14

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