4(4x-3)+2=6x+20

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Solution for 4(4x-3)+2=6x+20 equation: 



4(4x-3)+2=6x+20

We move all terms to the left:

4(4x-3)+2-(6x+20)=0

We multiply parentheses

16x-(6x+20)-12+2=0

We get rid of parentheses

16x-6x-20-12+2=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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