4(4x-3)=6(x-12)

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Solution for 4(4x-3)=6(x-12) equation: 



4(4x-3)=6(x-12)

We move all terms to the left:

4(4x-3)-(6(x-12))=0

We multiply parentheses

16x-(6(x-12))-12=0



We calculate terms in parentheses: -(6(x-12)), so:

6(x-12)

We multiply parentheses

6x-72

Back to the equation:

-(6x-72)



We get rid of parentheses

16x-6x+72-12=0

We add all the numbers together, and all the variables

10x+60=0

We move all terms containing x to the left, all other terms to the right

10x=-60

x=-60/10

x=-6

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