4(4x-3)=8(2x-2)+4

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Solution for 4(4x-3)=8(2x-2)+4 equation: 


Simplifying
4(4x + -3) = 8(2x + -2) + 4

Reorder the terms:
4(-3 + 4x) = 8(2x + -2) + 4
(-3 * 4 + 4x * 4) = 8(2x + -2) + 4
(-12 + 16x) = 8(2x + -2) + 4

Reorder the terms:
-12 + 16x = 8(-2 + 2x) + 4
-12 + 16x = (-2 * 8 + 2x * 8) + 4
-12 + 16x = (-16 + 16x) + 4

Reorder the terms:
-12 + 16x = -16 + 4 + 16x

Combine like terms: -16 + 4 = -12
-12 + 16x = -12 + 16x

Add '12' to each side of the equation.
-12 + 12 + 16x = -12 + 12 + 16x

Combine like terms: -12 + 12 = 0
0 + 16x = -12 + 12 + 16x
16x = -12 + 12 + 16x

Combine like terms: -12 + 12 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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