4(4x-4)+21=16(x+1)

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Solution for 4(4x-4)+21=16(x+1) equation: 



4(4x-4)+21=16(x+1)

We move all terms to the left:

4(4x-4)+21-(16(x+1))=0

We multiply parentheses

16x-(16(x+1))-16+21=0



We calculate terms in parentheses: -(16(x+1)), so:

16(x+1)

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)



We add all the numbers together, and all the variables

16x-(16x+16)+5=0

We get rid of parentheses

16x-16x-16+5=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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