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4(4x-4)+4x=3(5x-7)
We move all terms to the left:
4(4x-4)+4x-(3(5x-7))=0
We add all the numbers together, and all the variables
4x+4(4x-4)-(3(5x-7))=0
We multiply parentheses
4x+16x-(3(5x-7))-16=0
We calculate terms in parentheses: -(3(5x-7)), so:We add all the numbers together, and all the variables
3(5x-7)
We multiply parentheses
15x-21
Back to the equation:
-(15x-21)
20x-(15x-21)-16=0
We get rid of parentheses
20x-15x+21-16=0
We add all the numbers together, and all the variables
5x+5=0
We move all terms containing x to the left, all other terms to the right
5x=-5
x=-5/5
x=-1
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