4(4x-5)=34-4(x-2)

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Solution for 4(4x-5)=34-4(x-2) equation: 



4(4x-5)=34-4(x-2)

We move all terms to the left:

4(4x-5)-(34-4(x-2))=0

We multiply parentheses

16x-(34-4(x-2))-20=0



We calculate terms in parentheses: -(34-4(x-2)), so:

34-4(x-2)

determiningTheFunctionDomain
-4(x-2)+34

We multiply parentheses

-4x+8+34

We add all the numbers together, and all the variables

-4x+42

Back to the equation:

-(-4x+42)



We get rid of parentheses

16x+4x-42-20=0

We add all the numbers together, and all the variables

20x-62=0

We move all terms containing x to the left, all other terms to the right

20x=62

x=62/20

x=3+1/10

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