4(4x-7)-3=4(x-4)+45

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Solution for 4(4x-7)-3=4(x-4)+45 equation:



4(4x-7)-3=4(x-4)+45
We move all terms to the left:
4(4x-7)-3-(4(x-4)+45)=0
We multiply parentheses
16x-(4(x-4)+45)-28-3=0
We calculate terms in parentheses: -(4(x-4)+45), so:
4(x-4)+45
We multiply parentheses
4x-16+45
We add all the numbers together, and all the variables
4x+29
Back to the equation:
-(4x+29)
We add all the numbers together, and all the variables
16x-(4x+29)-31=0
We get rid of parentheses
16x-4x-29-31=0
We add all the numbers together, and all the variables
12x-60=0
We move all terms containing x to the left, all other terms to the right
12x=60
x=60/12
x=5

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