4(4x-7)-5=4(x-3)+51

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Solution for 4(4x-7)-5=4(x-3)+51 equation: 



4(4x-7)-5=4(x-3)+51

We move all terms to the left:

4(4x-7)-5-(4(x-3)+51)=0

We multiply parentheses

16x-(4(x-3)+51)-28-5=0



We calculate terms in parentheses: -(4(x-3)+51), so:

4(x-3)+51

We multiply parentheses

4x-12+51

We add all the numbers together, and all the variables

4x+39

Back to the equation:

-(4x+39)



We add all the numbers together, and all the variables

16x-(4x+39)-33=0

We get rid of parentheses

16x-4x-39-33=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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