4(4x-8)-6=4(x-3)+34

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Solution for 4(4x-8)-6=4(x-3)+34 equation: 



4(4x-8)-6=4(x-3)+34

We move all terms to the left:

4(4x-8)-6-(4(x-3)+34)=0

We multiply parentheses

16x-(4(x-3)+34)-32-6=0



We calculate terms in parentheses: -(4(x-3)+34), so:

4(x-3)+34

We multiply parentheses

4x-12+34

We add all the numbers together, and all the variables

4x+22

Back to the equation:

-(4x+22)



We add all the numbers together, and all the variables

16x-(4x+22)-38=0

We get rid of parentheses

16x-4x-22-38=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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