4(4x-8)=16(x-2)

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Solution for 4(4x-8)=16(x-2) equation:


Simplifying
4(4x + -8) = 16(x + -2)

Reorder the terms:
4(-8 + 4x) = 16(x + -2)
(-8 * 4 + 4x * 4) = 16(x + -2)
(-32 + 16x) = 16(x + -2)

Reorder the terms:
-32 + 16x = 16(-2 + x)
-32 + 16x = (-2 * 16 + x * 16)
-32 + 16x = (-32 + 16x)

Add '32' to each side of the equation.
-32 + 32 + 16x = -32 + 32 + 16x

Combine like terms: -32 + 32 = 0
0 + 16x = -32 + 32 + 16x
16x = -32 + 32 + 16x

Combine like terms: -32 + 32 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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