4(4x-9)-3=4(x-4)+49

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Solution for 4(4x-9)-3=4(x-4)+49 equation:



4(4x-9)-3=4(x-4)+49
We move all terms to the left:
4(4x-9)-3-(4(x-4)+49)=0
We multiply parentheses
16x-(4(x-4)+49)-36-3=0
We calculate terms in parentheses: -(4(x-4)+49), so:
4(x-4)+49
We multiply parentheses
4x-16+49
We add all the numbers together, and all the variables
4x+33
Back to the equation:
-(4x+33)
We add all the numbers together, and all the variables
16x-(4x+33)-39=0
We get rid of parentheses
16x-4x-33-39=0
We add all the numbers together, and all the variables
12x-72=0
We move all terms containing x to the left, all other terms to the right
12x=72
x=72/12
x=6

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