4(4x-9)-8=4(x-4)+56

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Solution for 4(4x-9)-8=4(x-4)+56 equation:



4(4x-9)-8=4(x-4)+56
We move all terms to the left:
4(4x-9)-8-(4(x-4)+56)=0
We multiply parentheses
16x-(4(x-4)+56)-36-8=0
We calculate terms in parentheses: -(4(x-4)+56), so:
4(x-4)+56
We multiply parentheses
4x-16+56
We add all the numbers together, and all the variables
4x+40
Back to the equation:
-(4x+40)
We add all the numbers together, and all the variables
16x-(4x+40)-44=0
We get rid of parentheses
16x-4x-40-44=0
We add all the numbers together, and all the variables
12x-84=0
We move all terms containing x to the left, all other terms to the right
12x=84
x=84/12
x=7

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