4(4y+-10)=40

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Solution for 4(4y+-10)=40 equation: 



4(4y+-10)=40

We move all terms to the left:

4(4y+-10)-(40)=0

We add all the numbers together, and all the variables

4(4y-10)-40=0

We multiply parentheses

16y-40-40=0

We add all the numbers together, and all the variables

16y-80=0

We move all terms containing y to the left, all other terms to the right

16y=80

y=80/16

y=5

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