4(4y+2)=2(1=6y)+8

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Solution for 4(4y+2)=2(1=6y)+8 equation: 



4(4y+2)=2(1=6y)+8

We move all terms to the left:

4(4y+2)-(2(1)=0

We add all the numbers together, and all the variables

4(4y+2)=0

We multiply parentheses

16y+8=0

We move all terms containing y to the left, all other terms to the right

16y=-8

y=-8/16

y=-1/2

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