4(4y+3)+3=5(6y-1)+2

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Solution for 4(4y+3)+3=5(6y-1)+2 equation: 



4(4y+3)+3=5(6y-1)+2

We move all terms to the left:

4(4y+3)+3-(5(6y-1)+2)=0

We multiply parentheses

16y-(5(6y-1)+2)+12+3=0



We calculate terms in parentheses: -(5(6y-1)+2), so:

5(6y-1)+2

We multiply parentheses

30y-5+2

We add all the numbers together, and all the variables

30y-3

Back to the equation:

-(30y-3)



We add all the numbers together, and all the variables

16y-(30y-3)+15=0

We get rid of parentheses

16y-30y+3+15=0

We add all the numbers together, and all the variables

-14y+18=0

We move all terms containing y to the left, all other terms to the right

-14y=-18

y=-18/-14

y=1+2/7

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