4(4y+3)-(y-5)=62

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Solution for 4(4y+3)-(y-5)=62 equation: 



4(4y+3)-(y-5)=62

We move all terms to the left:

4(4y+3)-(y-5)-(62)=0

We multiply parentheses

16y-(y-5)+12-62=0

We get rid of parentheses

16y-y+5+12-62=0

We add all the numbers together, and all the variables

15y-45=0

We move all terms containing y to the left, all other terms to the right

15y=45

y=45/15

y=3

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