4(4y-1)+3-2(3+y)=0

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Solution for 4(4y-1)+3-2(3+y)=0 equation:


Simplifying
4(4y + -1) + 3 + -2(3 + y) = 0

Reorder the terms:
4(-1 + 4y) + 3 + -2(3 + y) = 0
(-1 * 4 + 4y * 4) + 3 + -2(3 + y) = 0
(-4 + 16y) + 3 + -2(3 + y) = 0
-4 + 16y + 3 + (3 * -2 + y * -2) = 0
-4 + 16y + 3 + (-6 + -2y) = 0

Reorder the terms:
-4 + 3 + -6 + 16y + -2y = 0

Combine like terms: -4 + 3 = -1
-1 + -6 + 16y + -2y = 0

Combine like terms: -1 + -6 = -7
-7 + 16y + -2y = 0

Combine like terms: 16y + -2y = 14y
-7 + 14y = 0

Solving
-7 + 14y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 14y = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 14y = 0 + 7
14y = 0 + 7

Combine like terms: 0 + 7 = 7
14y = 7

Divide each side by '14'.
y = 0.5

Simplifying
y = 0.5

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