4(4y-1)+3y=15

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Solution for 4(4y-1)+3y=15 equation: 



4(4y-1)+3y=15

We move all terms to the left:

4(4y-1)+3y-(15)=0

We add all the numbers together, and all the variables

3y+4(4y-1)-15=0

We multiply parentheses

3y+16y-4-15=0

We add all the numbers together, and all the variables

19y-19=0

We move all terms containing y to the left, all other terms to the right

19y=19

y=19/19

y=1

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