4(4y-1)=12

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Solution for 4(4y-1)=12 equation: 



4(4y-1)=12

We move all terms to the left:

4(4y-1)-(12)=0

We multiply parentheses

16y-4-12=0

We add all the numbers together, and all the variables

16y-16=0

We move all terms containing y to the left, all other terms to the right

16y=16

y=16/16

y=1

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