4(4y-2)-9=5(2y-1)-18

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Solution for 4(4y-2)-9=5(2y-1)-18 equation: 



4(4y-2)-9=5(2y-1)-18

We move all terms to the left:

4(4y-2)-9-(5(2y-1)-18)=0

We multiply parentheses

16y-(5(2y-1)-18)-8-9=0



We calculate terms in parentheses: -(5(2y-1)-18), so:

5(2y-1)-18

We multiply parentheses

10y-5-18

We add all the numbers together, and all the variables

10y-23

Back to the equation:

-(10y-23)



We add all the numbers together, and all the variables

16y-(10y-23)-17=0

We get rid of parentheses

16y-10y+23-17=0

We add all the numbers together, and all the variables

6y+6=0

We move all terms containing y to the left, all other terms to the right

6y=-6

y=-6/6

y=-1

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