4(4y-3)-(y-5)=-32

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Solution for 4(4y-3)-(y-5)=-32 equation: 



4(4y-3)-(y-5)=-32

We move all terms to the left:

4(4y-3)-(y-5)-(-32)=0

We add all the numbers together, and all the variables

4(4y-3)-(y-5)+32=0

We multiply parentheses

16y-(y-5)-12+32=0

We get rid of parentheses

16y-y+5-12+32=0

We add all the numbers together, and all the variables

15y+25=0

We move all terms containing y to the left, all other terms to the right

15y=-25

y=-25/15

y=-1+2/3

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