4(4y-3)-(y-5)=32

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Solution for 4(4y-3)-(y-5)=32 equation: 



4(4y-3)-(y-5)=32

We move all terms to the left:

4(4y-3)-(y-5)-(32)=0

We multiply parentheses

16y-(y-5)-12-32=0

We get rid of parentheses

16y-y+5-12-32=0

We add all the numbers together, and all the variables

15y-39=0

We move all terms containing y to the left, all other terms to the right

15y=39

y=39/15

y=2+3/5

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