4(4y-3)=16y-12

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Solution for 4(4y-3)=16y-12 equation: 


Simplifying
4(4y + -3) = 16y + -12

Reorder the terms:
4(-3 + 4y) = 16y + -12
(-3 * 4 + 4y * 4) = 16y + -12
(-12 + 16y) = 16y + -12

Reorder the terms:
-12 + 16y = -12 + 16y

Add '12' to each side of the equation.
-12 + 12 + 16y = -12 + 12 + 16y

Combine like terms: -12 + 12 = 0
0 + 16y = -12 + 12 + 16y
16y = -12 + 12 + 16y

Combine like terms: -12 + 12 = 0
16y = 0 + 16y
16y = 16y

Add '-16y' to each side of the equation.
16y + -16y = 16y + -16y

Combine like terms: 16y + -16y = 0
0 = 16y + -16y

Combine like terms: 16y + -16y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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