4(4y-6)=-4(2y+18)

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Solution for 4(4y-6)=-4(2y+18) equation: 



4(4y-6)=-4(2y+18)

We move all terms to the left:

4(4y-6)-(-4(2y+18))=0

We multiply parentheses

16y-(-4(2y+18))-24=0



We calculate terms in parentheses: -(-4(2y+18)), so:

-4(2y+18)

We multiply parentheses

-8y-72

Back to the equation:

-(-8y-72)



We get rid of parentheses

16y+8y+72-24=0

We add all the numbers together, and all the variables

24y+48=0

We move all terms containing y to the left, all other terms to the right

24y=-48

y=-48/24

y=-2

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