4(5+2b)=28

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Solution for 4(5+2b)=28 equation: 



4(5+2b)=28

We move all terms to the left:

4(5+2b)-(28)=0

We add all the numbers together, and all the variables

4(2b+5)-28=0

We multiply parentheses

8b+20-28=0

We add all the numbers together, and all the variables

8b-8=0

We move all terms containing b to the left, all other terms to the right

8b=8

b=8/8

b=1

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