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4(5+3v)=4(5v-3)
We move all terms to the left:
4(5+3v)-(4(5v-3))=0
We add all the numbers together, and all the variables
4(3v+5)-(4(5v-3))=0
We multiply parentheses
12v-(4(5v-3))+20=0
We calculate terms in parentheses: -(4(5v-3)), so:We get rid of parentheses
4(5v-3)
We multiply parentheses
20v-12
Back to the equation:
-(20v-12)
12v-20v+12+20=0
We add all the numbers together, and all the variables
-8v+32=0
We move all terms containing v to the left, all other terms to the right
-8v=-32
v=-32/-8
v=+4
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