4(5+6d)=32

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Solution for 4(5+6d)=32 equation: 



4(5+6d)=32

We move all terms to the left:

4(5+6d)-(32)=0

We add all the numbers together, and all the variables

4(6d+5)-32=0

We multiply parentheses

24d+20-32=0

We add all the numbers together, and all the variables

24d-12=0

We move all terms containing d to the left, all other terms to the right

24d=12

d=12/24

d=1/2

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