4(5+t)+(t)+9(t-2)=19

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Solution for 4(5+t)+(t)+9(t-2)=19 equation: 



4(5+t)+(t)+9(t-2)=19

We move all terms to the left:

4(5+t)+(t)+9(t-2)-(19)=0

We add all the numbers together, and all the variables

4(t+5)+t+9(t-2)-19=0

We add all the numbers together, and all the variables

t+4(t+5)+9(t-2)-19=0

We multiply parentheses

t+4t+9t+20-18-19=0

We add all the numbers together, and all the variables

14t-17=0

We move all terms containing t to the left, all other terms to the right

14t=17

t=17/14

t=1+3/14

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