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4(5-(4-2x))+2x=2(5x+3)-2
We move all terms to the left:
4(5-(4-2x))+2x-(2(5x+3)-2)=0
We add all the numbers together, and all the variables
4(5-(-2x+4))+2x-(2(5x+3)-2)=0
We add all the numbers together, and all the variables
2x+4(5-(-2x+4))-(2(5x+3)-2)=0
We calculate terms in parentheses: -(2(5x+3)-2), so:We get rid of parentheses
2(5x+3)-2
We multiply parentheses
10x+6-2
We add all the numbers together, and all the variables
10x+4
Back to the equation:
-(10x+4)
2x+4(5-(-2x+4))-10x-4=0
We add all the numbers together, and all the variables
-8x+4(5-(-2x+4))-4=0
We move all terms containing x to the left, all other terms to the right
-8x+4(5-(-2x+4))=4
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