4(5-3x)+12=3(4-4x)+20

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Solution for 4(5-3x)+12=3(4-4x)+20 equation: 


Simplifying
4(5 + -3x) + 12 = 3(4 + -4x) + 20
(5 * 4 + -3x * 4) + 12 = 3(4 + -4x) + 20
(20 + -12x) + 12 = 3(4 + -4x) + 20

Reorder the terms:
20 + 12 + -12x = 3(4 + -4x) + 20

Combine like terms: 20 + 12 = 32
32 + -12x = 3(4 + -4x) + 20
32 + -12x = (4 * 3 + -4x * 3) + 20
32 + -12x = (12 + -12x) + 20

Reorder the terms:
32 + -12x = 12 + 20 + -12x

Combine like terms: 12 + 20 = 32
32 + -12x = 32 + -12x

Add '-32' to each side of the equation.
32 + -32 + -12x = 32 + -32 + -12x

Combine like terms: 32 + -32 = 0
0 + -12x = 32 + -32 + -12x
-12x = 32 + -32 + -12x

Combine like terms: 32 + -32 = 0
-12x = 0 + -12x
-12x = -12x

Add '12x' to each side of the equation.
-12x + 12x = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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