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4(5-3x)=2(5x-4)+2(2-x)
We move all terms to the left:
4(5-3x)-(2(5x-4)+2(2-x))=0
We add all the numbers together, and all the variables
4(-3x+5)-(2(5x-4)+2(-1x+2))=0
We multiply parentheses
-12x-(2(5x-4)+2(-1x+2))+20=0
We calculate terms in parentheses: -(2(5x-4)+2(-1x+2)), so:We get rid of parentheses
2(5x-4)+2(-1x+2)
We multiply parentheses
10x-2x-8+4
We add all the numbers together, and all the variables
8x-4
Back to the equation:
-(8x-4)
-12x-8x+4+20=0
We add all the numbers together, and all the variables
-20x+24=0
We move all terms containing x to the left, all other terms to the right
-20x=-24
x=-24/-20
x=1+1/5
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