4(5-c)-32=26c-6(2+5c)

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Solution for 4(5-c)-32=26c-6(2+5c) equation:


Simplifying
4(5 + -1c) + -32 = 26c + -6(2 + 5c)
(5 * 4 + -1c * 4) + -32 = 26c + -6(2 + 5c)
(20 + -4c) + -32 = 26c + -6(2 + 5c)

Reorder the terms:
20 + -32 + -4c = 26c + -6(2 + 5c)

Combine like terms: 20 + -32 = -12
-12 + -4c = 26c + -6(2 + 5c)
-12 + -4c = 26c + (2 * -6 + 5c * -6)
-12 + -4c = 26c + (-12 + -30c)

Reorder the terms:
-12 + -4c = -12 + 26c + -30c

Combine like terms: 26c + -30c = -4c
-12 + -4c = -12 + -4c

Add '12' to each side of the equation.
-12 + 12 + -4c = -12 + 12 + -4c

Combine like terms: -12 + 12 = 0
0 + -4c = -12 + 12 + -4c
-4c = -12 + 12 + -4c

Combine like terms: -12 + 12 = 0
-4c = 0 + -4c
-4c = -4c

Add '4c' to each side of the equation.
-4c + 4c = -4c + 4c

Combine like terms: -4c + 4c = 0
0 = -4c + 4c

Combine like terms: -4c + 4c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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