4(5-x)-(x+2)=6+8(x-5)

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Solution for 4(5-x)-(x+2)=6+8(x-5) equation: 



4(5-x)-(x+2)=6+8(x-5)

We move all terms to the left:

4(5-x)-(x+2)-(6+8(x-5))=0

We add all the numbers together, and all the variables

4(-1x+5)-(x+2)-(6+8(x-5))=0

We multiply parentheses

-4x-(x+2)-(6+8(x-5))+20=0

We get rid of parentheses

-4x-x-(6+8(x-5))-2+20=0



We calculate terms in parentheses: -(6+8(x-5)), so:

6+8(x-5)

determiningTheFunctionDomain
8(x-5)+6

We multiply parentheses

8x-40+6

We add all the numbers together, and all the variables

8x-34

Back to the equation:

-(8x-34)



We add all the numbers together, and all the variables

-5x-(8x-34)+18=0

We get rid of parentheses

-5x-8x+34+18=0

We add all the numbers together, and all the variables

-13x+52=0

We move all terms containing x to the left, all other terms to the right

-13x=-52

x=-52/-13

x=+4

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