4(5b-2)=27

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Solution for 4(5b-2)=27 equation: 



4(5b-2)=27

We move all terms to the left:

4(5b-2)-(27)=0

We multiply parentheses

20b-8-27=0

We add all the numbers together, and all the variables

20b-35=0

We move all terms containing b to the left, all other terms to the right

20b=35

b=35/20

b=1+3/4

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