4(5c+1)-42=15c+2

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Solution for 4(5c+1)-42=15c+2 equation: 



4(5c+1)-42=15c+2

We move all terms to the left:

4(5c+1)-42-(15c+2)=0

We multiply parentheses

20c-(15c+2)+4-42=0

We get rid of parentheses

20c-15c-2+4-42=0

We add all the numbers together, and all the variables

5c-40=0

We move all terms containing c to the left, all other terms to the right

5c=40

c=40/5

c=8

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