4(5c+3)=9c+74(5c+3)=9c+7

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Solution for 4(5c+3)=9c+74(5c+3)=9c+7 equation: 



4(5c+3)=9c+74(5c+3)=9c+7

We move all terms to the left:

4(5c+3)-(9c+74(5c+3))=0

We multiply parentheses

20c-(9c+74(5c+3))+12=0



We calculate terms in parentheses: -(9c+74(5c+3)), so:

9c+74(5c+3)

We multiply parentheses

9c+370c+222

We add all the numbers together, and all the variables

379c+222

Back to the equation:

-(379c+222)



We get rid of parentheses

20c-379c-222+12=0

We add all the numbers together, and all the variables

-359c-210=0

We move all terms containing c to the left, all other terms to the right

-359c=210

c=210/-359

c=-210/359

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