4(5t+1)-6=t-(t1)

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Solution for 4(5t+1)-6=t-(t1) equation: 



4(5t+1)-6=t-(t1)

We move all terms to the left:

4(5t+1)-6-(t-(t1))=0

We add all the numbers together, and all the variables

4(5t+1)-6-0=0

We add all the numbers together, and all the variables

4(5t+1)-6=0

We multiply parentheses

20t+4-6=0

We add all the numbers together, and all the variables

20t-2=0

We move all terms containing t to the left, all other terms to the right

20t=2

t=2/20

t=1/10

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