4(5t+3)+t=6(t+2)

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Solution for 4(5t+3)+t=6(t+2) equation: 



4(5t+3)+t=6(t+2)

We move all terms to the left:

4(5t+3)+t-(6(t+2))=0

We add all the numbers together, and all the variables

t+4(5t+3)-(6(t+2))=0

We multiply parentheses

t+20t-(6(t+2))+12=0



We calculate terms in parentheses: -(6(t+2)), so:

6(t+2)

We multiply parentheses

6t+12

Back to the equation:

-(6t+12)



We add all the numbers together, and all the variables

21t-(6t+12)+12=0

We get rid of parentheses

21t-6t-12+12=0

We add all the numbers together, and all the variables

15t=0

t=0/15

t=0

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