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4(5t-1)=3(2t+1)
We move all terms to the left:
4(5t-1)-(3(2t+1))=0
We multiply parentheses
20t-(3(2t+1))-4=0
We calculate terms in parentheses: -(3(2t+1)), so:We get rid of parentheses
3(2t+1)
We multiply parentheses
6t+3
Back to the equation:
-(6t+3)
20t-6t-3-4=0
We add all the numbers together, and all the variables
14t-7=0
We move all terms containing t to the left, all other terms to the right
14t=7
t=7/14
t=1/2
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