4(5t-3)=128

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Solution for 4(5t-3)=128 equation: 



4(5t-3)=128

We move all terms to the left:

4(5t-3)-(128)=0

We multiply parentheses

20t-12-128=0

We add all the numbers together, and all the variables

20t-140=0

We move all terms containing t to the left, all other terms to the right

20t=140

t=140/20

t=7

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