4(5t-6)=31t-7

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Solution for 4(5t-6)=31t-7 equation: 



4(5t-6)=31t-7

We move all terms to the left:

4(5t-6)-(31t-7)=0

We multiply parentheses

20t-(31t-7)-24=0

We get rid of parentheses

20t-31t+7-24=0

We add all the numbers together, and all the variables

-11t-17=0

We move all terms containing t to the left, all other terms to the right

-11t=17

t=17/-11

t=-1+6/11

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