4(5x+1)(5x+1)=0

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Solution for 4(5x+1)(5x+1)=0 equation: 



4(5x+1)(5x+1)=0

We multiply parentheses ..

4(+25x^2+5x+5x+1)=0

We multiply parentheses

100x^2+20x+20x+4=0

We add all the numbers together, and all the variables

100x^2+40x+4=0

a = 100; b = 40; c = +4;
Δ = b2-4ac
Δ = 402-4·100·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{200}=-1/5$

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