4(5x+1)=1/2(20x+16)+(16

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Solution for 4(5x+1)=1/2(20x+16)+(16 equation: 



4(5x+1)=1/2(20x+16)+(16

We move all terms to the left:

4(5x+1)-(1/2(20x+16)+(16)=0



Domain of the equation: 2(20x+16)+16!=0

We move all terms containing x to the left, all other terms to the right

2(20x+16)!=-16

x∈R



We multiply parentheses

20x-(1/2(20x+16)+16+4=0

We multiply all the terms by the denominator


20x*2(20x+16)+16+4-(1=0

We add all the numbers together, and all the variables

20x*2(20x+16)=0

Wy multiply elements

40x^2(2=0

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